查看完整版本 : 求大師解答 電磁感應 1小題

菊花仔 2013-10-30 05:45 PM

求大師解答 電磁感應 1小題

[font=SimSun][size=10.5pt]如圖,在磁感應強度為B=0.1T的勻強磁場中,有一個直角三角形線框abc,如圖所示,線框以v=2m/s的速度沿圖示方向(與bc邊平行)勻速運動,己知ab=0.1m,角θ=30°,線框總電阻R=0.2Ω,則ac、bc、ab三條線段上的感應電動勢分別為Eac=__________v,Ebc=_________V,Ead=_________V,它們的方向如何[/size][/font]
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[font=SimSun][size=10.5pt]小弟就百思不得其解 磁通量不是應該沒有變化嗎
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↗亢龍無悔↙ 2013-10-31 08:37 AM

[quote]原帖由 [i]菊花仔[/i] 於 30-10-2013 05:45 PM 發表 [url=http://www.discuss.com.hk/redirect.php?goto=findpost&pid=374721231&ptid=22616602][img]http://www.discuss.com.hk/images/common/back.gif[/img][/url]如圖,在磁感應強度為B=0.1T的勻強磁場中,有一個直角三角形線框abc,如圖所示,線框以v=2m/s的速度沿圖示方向(與bc邊平行)勻速運動,己知ab=0.1m,角θ=30°,線框總電阻R=0.2Ω,則ac、bc、ab三條線段上的感應電 ... [/quote]e.m.f. = B l v and V = I R
You can get the answer.
The direction can be determined by fleming's right hand rule.
Note that the current flow will be from b to a and c to a with same magnitude. Therefore, the overall current within the coil will be 0.

Replying to your question, there have current flows when you look at each individual component. When they join together, current = 0



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菊花仔 2013-11-10 08:40 PM

[quote]原帖由 [i]↗亢龍無悔↙[/i] 於 2013-10-31 08:37 AM 發表 [url=http://www.discuss.com.hk/redirect.php?goto=findpost&pid=374758323&ptid=22616602][img]http://www.discuss.com.hk/images/common/back.gif[/img][/url]
e.m.f. = B l v and V = I R
You can get the answer.
The direction can be determined by fleming's right hand rule.
Note that the current flow will be from b to a and c to a with same magnitude. Theref ... [/quote]

師兄, 我想問
Triangle 'S magnetic flux didn't change
why have e.m.f.?
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