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Walter仔~ 2013-10-17 02:59 PM

條功課唔識做 關於電

According to "Fleming's left-hand rule" , when current flows in a wire,and an external magnetic field is applied across that flow, the wire experiences a force perpendicular both to that field and to the direction of the current flow.
(i) find the Thrust of Motion c-> generated on the conducting wire if
the vector of current flow is a> = 2i^ + 3j^ +2k^ .
the vector of magnetic field is b> =i^ - j^ +2k^

(ii)
Show that the vector of force c> is perpendicular to vector of current flow a> .

唔該指教一下我 :smile_27:

↗亢龍無悔↙ 2013-10-17 06:19 PM

Try to use cross product. I cross B , you can get the force



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Walter仔~ 2013-10-17 07:44 PM

OK TRY THX
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